EXERCISE 7.2 — STEP BY STEP SOLUTIONS
1. During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at ₹1450 and two shirts marked at ₹850 each?
Discount on Jeans = 10% of ₹1450 = \(\dfrac{10}{100} \times 1450 = 145\)
Price to pay = ₹1450 – ₹145 = ₹1305
Each shirt: Discount = 10% of ₹850 = \(\dfrac{10}{100} \times 850 = 85\)
Price to pay = ₹850 – ₹85 = ₹765
For 2 shirts = ₹765 × 2 = ₹1530
Step 2: Add jeans and shirts = ₹1305 + ₹1530 = ₹2835
Answer: The customer pays ₹2835.
2. The price of a TV is ₹13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.
Sales Tax = 12% of ₹13,000 = \(\dfrac{12}{100} \times 13000 = 1560\)
Total amount = Price + Tax = ₹13,000 + ₹1560 = ₹14,560
Answer: Vinod pays ₹14,560.
3. Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is ₹1,600, find the marked price.
Paid = 80% of Marked Price
Let Marked Price = M
\(0.80M = 1600\)
\(M = \dfrac{1600}{0.80} = 2000\)
Answer: Marked Price = ₹2000.
4. I purchased a hair-dryer for ₹5,400 including 8% VAT. Find the price before VAT was added.
Let Price before VAT = P
Including VAT = \(P + 8\% \text{ of } P = 1.08P\)
\(1.08P = 5400\)
\(P = \dfrac{5400}{1.08} = 5000\)
VAT amount = ₹5400 – ₹5000 = ₹400
Answer: Price before VAT = ₹5000
5. An article was purchased for ₹1239 including GST of 18%. Find the price of the article before GST was added.
Let Price before GST = \(x\)
Price including GST = \(x + 18\% \text{ of } x = x + \frac {18}{100} \times x= 1.18x\)
By the question:
\(1.18x = 1239\) => \(x = \dfrac{1239}{1.18} = 1050\)
GST amount = ₹1239 – ₹1050 = ₹189
Answer: Price before GST = ₹1239-₹189= ₹1050