EXERCISE 1.2

1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.

Tickets sold on the first day = 1094

Tickets sold on the second day = 1812

Tickets sold on the third day = 2050

Tickets sold on the final day = 2751

Total number of tickets = \( 1094 + 1812 + 2050 + 2751 \)

Solution for question 1

Total number of tickets = 7707

Total tickets sold = 7,707.
2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

Runs wished to complete = 10,000

Runs scored so far = 6,980

More runs needed = \( 10,000 - 6,980 \)

Solution for question 2

More runs needed = 3,020

Shekhar needs 3,020 more runs.
3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Votes of successful candidate = 5,77,500

Votes of nearest rival = 3,48,700

Margin of win = \( 5,77,500 - 3,48,700 \)

Solution for question 3

Margin of win = 2,28,800

The successful candidate won by a margin of 2,28,800 votes.
4. Kirti bookstore sold books worth ₹ 2,85,891 in the first week of June and books worth ₹ 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Total sale for two weeks:

Sale in first week = ₹ 2,85,891

Sale in second week = ₹ 4,00,768

Total sale = \( 2,85,891 + 4,00,768 \)

Total sale = ₹ 6,86,659

Which week had greater sale and by how much?

Since \( 4,00,768 > 2,85,891 \), the sale was greater in the second week.

Difference = \( 4,00,768 - 2,85,891 \)

Solution for question 4

Difference = ₹ 1,14,877

The total sale was ₹ 6,86,659. The sale was greater in the second week by ₹ 1,14,877.
5. Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.

To form the greatest number, arrange the digits in descending order: 7, 6, 4, 3, 2.

Greatest number = 76,432

To form the least number, arrange the digits in ascending order: 2, 3, 4, 6, 7.

Least number = 23,467

Difference = Greatest number - Least number

Difference = \( 76,432 - 23,467 = 52,965 \)

Solution for question 5
The difference is 52,965.
6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?

Number of screws manufactured in one day = 2,825

Number of days in January = 31

Total screws = \( 2,825 \times 31 \)

Solution for question 6

Total screws = 87,575

The machine produced 87,575 screws in January 2006.
7. A merchant had ₹ 78,592 with her. She placed an order for purchasing 40 radio sets at ₹ 1200 each. How much money will remain with her after the purchase?

Total money with the merchant = ₹ 78,592

Cost of one radio set = ₹ 1,200

Number of radio sets purchased = 40

Total cost of 40 radio sets = \( 40 \times 1,200 = 48,000 \)

Money remaining = Total money - Total cost

Money remaining = \( 78,592 - 48,000 = 30,592 \)

Solution for question 7
₹ 30,592 will remain with the merchant.
8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)

Incorrect multiplier = 65

Correct multiplier = 56

The difference between the multipliers is \( 65 - 56 = 9 \).

The difference in the answers will be the number multiplied by this difference:

Difference = \( 7236 \times 9 = 65,124 \)

The answer was greater by 65,124.
9. To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: convert data in cm.)

Cloth needed for 1 shirt = 2 m 15 cm = \( (2 \times 100) + 15 = 215 \) cm

Total cloth available = 40 m = \( 40 \times 100 = 4000 \) cm

Number of shirts = Total cloth \(\div\) cloth per shirt

Number of shirts = \( 4000 \div 215 = 18 \) with a remainder.

Solution for question 9

Cloth used = \( 18 \times 215 = 3870 \) cm

Cloth remaining = \( 4000 - 3870 = 130 \) cm

Cloth remaining = 1 m 30 cm

18 shirts can be stitched, and 1 m 30 cm of cloth will remain.
10. Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

Weight of one box = 4 kg 500 g = \( (4 \times 1000) + 500 = 4500 \) g

Maximum van capacity = 800 kg = \( 800 \times 1000 = 8,00,000 \) g

Number of boxes = Total capacity \(\div\) weight per box

Number of boxes = \( 8,00,000 \div 4,500 = 177.77... \)

Solution for question 10

Since the number of boxes must be a whole number, we take the integer part.

177 boxes can be loaded into the van.
11. The distance between the school and a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.

Distance between house and school = 1 km 875 m = 1875 m

Distance covered in one day (both ways) = \( 1875 \times 2 = 3750 \) m

Total distance in six days = \( 3750 \times 6 = 22,500 \) m

Total distance in six days = 22 km 500 m

The student covers a total distance of 22 km 500 m in six days.
12. A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

Total amount of curd = 4 litres 500 ml = \( (4 \times 1000) + 500 = 4500 \) ml

Capacity of one glass = 25 ml

Number of glasses = Total amount of curd \(\div\) capacity per glass

Number of glasses = \( 4500 \div 25 = 180 \)

Solution for question 11
180 glasses can be filled with curd.